Sunday 27 March 2011

TTEC 4842 exp 2 (2

Components:
1 x resistor, 1 x diode, 1 x L.E.D
Exercise:
For Vs= 5v, R= 1Kohm, D= 1N007 build the following circuit on a breadboard:


Calculate first the value of the current flowing through the diode, now Measure and check your answer?show your working:
Calculated:

                  4.3/1000  = 0.0043/4.3mA


Measured: 4.60mA

Is the reading as you expected; explain why or why not?
The reading is pretty much exact as to what I expected it to be, it was slightly different due to the tolerance/resistance involved in the individual components involved in this experiment.
Calculate the voltage drop across the diode, now Measure and check your answer?

Calculated
: 0.7v

Measured: 0.4v

Using the data sheet given in Table 1,

What is the maximum value of the current that can flow through the given diode?
1A @ 75 degrees c
For R = 1Kohm. What is the maximum value of Vs so that the diode operates in a safe region?
1000v


Replace the diode with an L.E.D & calculate the current, then measure and check your answer?

Calculated: 3.1mA

Measured: 3.17mA

What do you observe? Explain briefly: V = Voltage
The resistor has a voltage drop because it is a consumer of V and is in series so the over all value of V is reduced after being partly consumed by the resistor. The L.E.D has a voltage drop of 1.83v because every L.E.D needs at least that amount of V to let current flow through the circuit and the drop is also due to resistance in both components.

4 comments:

  1. Some good work Joshua,Did you notice that the the LED had a higher volt drop? Although it is a diode(light emitting diode)it does use more voltage to push the electrons though

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  2. On your calculations can you show them so i can check that they are correct, the first one 1000=.0043/.43mA is a strange formula, are you just changing it from Amps to milliamp?

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  3. sorry, had my 4.3 typed up in the wrong place, made changes accordingly. but as you can see, what ive done here is figured out what my Vs (4.3) is after minusing the Vd for the diode (.7) I have then used ohms law (I/R=A) to calculate my current (4.3/1000=0.0043A or 4.3mA)

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