Monday 11 April 2011

TTEC 4284 exp 8

Results:


27k  rb: 4.10   vbe: .72   vce: .10   ib: 4.08   ic: 4.70

67k  rb: 4.11   vbe: .71   vce: .15   ib: 4.10   ic: 4.67

180k  rb: 4.14   vbe: .69   vce: .18   ib: 4.15   ic: 4.54

560k  rb: 4.17   vbe: .65   vce: .24   ib: 4.18   ic: 4.22

1m  rb: 4.24   vbe: 0.64   vce: .35 ib: 4.24   ic: 1.00

Discuss what happend to VCE during this experiment. What change took place, and what caused the change?
Whilst testing VCE, when the resistors were replaced with higher resistors the value of VCE raised due to the transistor acting as an amplifier, the higher the resistance is the more the transistor tries to make up for the volt drop.

Discuss what happend to VBE during this experiment. What change took place, and what caused the change?
When we were testing VBE the value decreased as higher resistors were added to the circuit. The reason for this is that the collector circuit is using more of the current supplied.

Discuss what happend to IB during this experiment. What change took place, and what caused the change?
When we tested Ib after attaching higher value resistors, the result we got was lower each time due to the increase of resistance at the collector, the base didnt get as much current.

Discuss what happend to IC during this experiment. What change took place, and what caused the change?
The value of IC kept decreasing due to there being less current provided to the base port because of the higher resistance at the collector port.



B = Ic/Ib
B = 4.24/0.1 = 42.4
B = 42.4


Explain what the load line graph is telling you. Discuss the regions of the graph where the transistor is Saturated, Cut-off, or in the Active area:
The load line graph indicates that most of the readings given are either just about in the cut-off region if not in the cut-off region, but one of our readings, the one that ranges up to 1.1mA on the Ib scale, shows that it is in the saturation area of this transistor.

2 comments:

  1. Your on the right track how ever their are a few things you have incorrect, this statement is not correct "Whilst testing VCE, when the resistors were replaced with higher resistors the value of VCE raised due to the transistor acting as an amplifier, the higher the resistance is the more the transistor tries to make up for the volt drop".
    It should be the higher the resister at the base the lower the current at the base which means the transistor is more closed or being switched off, this limits the current flow Vce which means more voltage is used to push the electrons across the Vce junction making the voltage or pressure difference higher this is what you are reading. Also noticed that your figures on the table Ib don't drop as you increases the Rb resistor i think you have then back to front. The figures in the table are a bit strange as they seem to be to uniform for this experiment, did you do this experiment your self?

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  2. Yes I think the figures are back to front aswell as my explanation. And yes i did the experiment myself?

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